The refractive index of water measured by the relation `m = (real depth)/ (apparent depth)` is found to have values of 1.34, 1.38, 1.32 and 1.36, the mean value of refractive index with percentage error is

The refractive index of water as measured by the relation p = (Real depth)/ (Apparent depth) was found to have the values 1.29, 1.33, 1.34, 1.35, 1.32, 1.36, 1.30, 1.33. Calculate mean value of p.

The refractive index of water as measured by the relation mu = ("Real depth")/("Apparent depth") was found to have the values 1.29 , 1.33 , 1.34 , 1.35 , 1.32 , 1.36 , 1.30 , 1.33 . Calculate (i) mean value of mu (ii) mean value of absolute error (iii) relative error (iv) percentage error .

Prove that Refractive index= ("real depth")/("apparent depth")

How is the refractive index of a medium related to the real and apparent depths of an object in that medium ?

If refractive measure of water are 1.32,1.33,1.34, 1.35 and 1.36 then find of absolute error, relative error and percentage error.

The refractive, index of water is found to be the values 1.29, 1.33,1.34, 1.35, 1.3, 1.36,1.30 and 1.33. Calculate the mean values, absolute errors relative error and percentage of error.

Find relation for refractive index in terms of real depth and apparent depth.

The refractive index (n) of glass is found to have the values 1.49,1.50,1.52,1.54 and 1.48. Calculate (i) the mean value of refractive index, (ii) absolute error in each measurement, (iii) mean absolute error, (iv) fractional error and (v) percentage error

The refractive index (n) of glass is found to have the values 1.49,1.50,1.52,1.54 and 1.48. Calculate (i) the mean value of refractive index, (ii) absolute error in each measurement, (iii) mean absolute error, (iv) fractional error and (v) percentage error

Derive the relation among apparent depth, real depth and refractive index of a medium.