`(cos 29^(@) + sin 29^(@))/(cos29^(@) - sin 29^(@))=`

If 0

If Tantheta = (Cos29^(@)+Sin29^(@))/(Cos29^(@)-Sin29^(@))andtheta is acute then theta =

cos 56 ^(@) + cos 58^(@) - cos 66^(@) - 4 cos 28^(@) cos 29^(@) sin 33 ^(@) =

(1+ cos 56^(@) + cos 58^(@) - cos 66^(@))/( cos 28^(@) cos 29^@ sin 33^(@) )=

Show that 1+cos 56^(@)+ cos 58^(@)-cos66^(@)=4 cos 28^(@) cos 29^(@) sin 33^(@)

(1+cos56^(@)+cos58^(@)-cos66^(@))/(cos28^(@)cos29^(@)sin33^(@))=

(1+cos56^(@)+cos58^(@) -cos66^(@))/(cos28^(@)cos29^@sin33^(@)) =

The value of [ ( sin^(2) 25^(@) + sin^(2) 65^(@))/(cos^(2) 24^(@) + cos^2 66^(@)) + sin^(2)61^(@) + cos 61^@ sin 29^(@)] is :

(1+cos 56^(@)+cos58^(@)-cos66^(@))/(cos28^(@)cos29^(@)sin33^(@))=kcos(A/2)cos(B/2)sin(c/2) then k=?