Home
Class 12
PHYSICS
The change in the magnitude of the volum...

The change in the magnitude of the volume of an ideal gas when a small additional pressure `DeltaP` is applied at a constant temperature, is the same as the change when the temperature is reduced by a small quantity `DeltaT` at constant pressure. The initial temperature and pressure of the gas were 300 K and 2 atm. respectively. If `|DeltaT|=C|DeltaP|` then value of C in (K/atm) is __________.

Promotional Banner

Similar Questions

Explore conceptually related problems

Volume of a gas is doubled by raising its temperature at constant pressure . Initial temperature of the gas was 13^@C . Find the final temperature.

Calculate the maximum work done by an ideal gas when pressure on 10 g of H_2 is reduced from 20 to 2 atm at a constant temperature 300 K.

10 itres of monoatomic gas at 0^(@) C and 10 atm pressure is suddenly released to 1 atm pressure and the gas expands adibatically against the constant pressure. The final temperature and the volume of the gas respectively are :

If the temperature of a gas is increased by 1K at constant pressure its volume increase by 0.0035 of the initial volume. The temperature of the gas is

A gas has a volume of 6.0L at a pressure of 0.80 atm. What is the volume if the pressure is changed to 0.20atm at constant temperature?

At a constant volume, a quantity of an ideal gas has a pressure of 800 mm Hg at 300 K. At what pressure, the temperature will be halved ?

At a constant volume, a quantity of an ideal gas has a pressure of 800 mm Hg at 300 K. At what pressure, the temperature will be halved ?

Calculate work done by 1 mole of ideal gas expand isothermally and irreversibly from pressure of 5 atm to 2 atm against a constant external pressure of 1 atm at 300 K temperature.

One mole of an ideal gas requires 207 J heat to raise the temperature by 10K When heated at constant pressure. If the same gas is heated at constant volume to raise the temperature by 5K, then the heat required is