At which distance along the centre axis of a uniformaly charged plastic disc of radius R is the magnitude of the electric field equal to one-half the magnitude of the field at the centre of the surface of the disc ?

At what distance along the central perpendicular axis of a uniformly charged plastic disk of radius 0.600 m is the magnitude of the electric field equal to 25% of the magnitude of the field at the center of the surface of the disk ?

Field Of Uniformaly Charged Disc

The surface charge density of a thin charged disc of radius R is sigma . The value of the electric field at the centre of the disc is (sigma)/(2in_(o)) . With respect to the field at the centre, the electric field along the axis at a distance R from the centre of the disc reduces by

The surface charge density of a thin charged disc of radius R is sigma . The value of the electric field at the centre of the disc (sigma)/(2 in_(0)) . With respect to the field at the centre, the electric field along the axis at a distance R from the centre of the disc is

A charge q is uniformly distributed over a quarter circular ring of radius r . The magnitude of electric field strength at the centre of the ring will be

For a uniformly charged ring of radius R, the electric field on its exis has the largest magnitude at a distance h from its centre. Then value of h is :