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The vertices of a triangle OBC are O(0,0...

The vertices of a triangle `OBC` are `O(0,0),B(-3,-1),C(-1,-3)`. Equation of line parallel to `BC` & intersecting the sides `OB` & `OC` whose perpendicular distance from the point `(0,0)` is `1/(sqrt(2))` is `ax+by+2=0` then the value of `(a^(4)+b^(4))/4` is

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