A body of mass `5 kg` at rest under the action of a force which gives its velocity given by `v = 3 xx t m//s`, here 't' is time in seconds. The work done by the force in two seconds will be

A body of mass 6 kg is acted upon by a force which causes a displacement in it given by x = t^2/4 meter, where t is the time in second. The work done by the force in 2 seconds is

A body of mass 3 kg is under a constant force which causes a displacement s metre in it, given by the relation s=(1)/(3)t^(2) , where t is in seconds. Work done by the force in 2 seconds is

A body of mass 3 kg is under a constant force which causes a displacement s metre in it, given by the relation s=(1)/(3)t^(2) , where t is in seconds. Work done by the force in 2 seconds is

The distance x moved by a body of mass 0.5 kg under the action of a force varies with time t as x(m)=3t^(2)+4t+5 Here, t is expressed in second. What is the work done by the force in first 2 seconds?

The distance x moved by a body of mass 0.5 kg under the action of a force varies with time t as x(m)=3t^(2)+4t+5 Here, t is expressed in second. What is the work done by the force in first 2 seconds?

The relation between the displaement x and the time t for a body of mass 2 kg moving under the action of a force is given by x=t^3//3 , where x is in metre and t in second . Calculate the work done by the body in the first 2 seconds .

A body of mass 6kg is under a force which causes displacement in it given by S= (t^(2))/(4) maters where t is time . The work done by the force in 2 sec is

A body of mass 6kg is under a force which causes displacement in it given by S= (t^(2))/(4) maters where t is time . The work done by the force in 2 sec is