A particle is moving in a striaght line according as `S=15t+6t^2-t^3`, then the time it will come to rest is

A particle is moving in a straight line according as s=45t+11t^2-t^3 then the time when it come to rest is

A particle is moving in a straight line according as s=45t+11t^2-t^3 then the time when it come to rest is: a) -9 seconds b) 5/3 seconds c) 9 seconds d) -5/3 seconds

A particle is moving along a straight line according to the law s=16+48t-t^3 . The distance travelled by the particle before coming to rest at an instant is

A particle is moving along a line according s= f(t) = 8t + t^3 . Find the initial velocity

If a particle moves is a straight line according to s=t^(3)-6t^(2)-15t , the time interval during which the velocity is negative and acceleration is positive is

The distance S metres moved by a particle traveling in a straight line in t second is given by S = 45t +11t^2-t^3 . Find the time when the particle comes to rest.

If a particle moves alonga straight line by S = 4t^(2) - 8t + 3 and the time at which the particle comes of rest is 't' seconds then '2t' is

A particle is moving in a striaght line and at a given time, its displacement is S = t^(3) - 6t^(2) + 9t , where t is in seconds and S is in meter . The total distance travelled by the particle during the first five seconds is

A particle is moving in a striaght line and at a given time, its displacement is S = t^(3) - 6t^(2) + 9t , where t is in seconds and S is in meter . The total distance travelled by the particle during the first five seconds is