If `tan 20^(@) =lamda,` then `(tan 160^(@) -tan 110^(@))/(1+ (tan 160^(@)) (tan 110^(@)))=`

If tan20^(@) = lambda then show that (tan 160^(@) -tan 110^(@))/(1+tan160^(@).tan110^(@)) = (1-lambda^2)/(2lambda) .

If tan 20^@ =p , " then " (tan 160^@ - tan 110^(@))/(1+ tan 160^(@) tan 110^(@))=

If tan 20^(@) = lambda , " then " (tan 250^@ + tan 340^(@))/(tan 200^(@) - tan 110^(@))=

If : p = cot 20^(@),"then": (tan 160^(@) - tan 110^(@))/(1 +tan 160^(@) * tan 110^(@))= A) (p^(2)-1)/(2p) B) (p^(2)+1)/(2p) C) (1-p^(2))/(2p) D) (2p)/(1 + p^(2))

tan 70^(@) - tan 20^(@)=

If tan20^@=lamda , then (tan160^@-tan110^@)/(1+(tan160^@)(tan110^@))=