`a^(2)+6a-567`

Factorise : (vii) 7a^(5) - 567 a

Fill in the blanks: (i) ... -:156=-2 (ii) ...-:567=-1

Fill in the blanks: (i) ... -:156=-2 (ii) ...-:567=-1

(cot333^(@)-cos567^(@))/(tan297^(@)+sin477^(@))=1

Find out the wrong term. 2, 6, 24, 96, 285, 568, 567

In a system of three particles, the linear momenta of the three particles are (1,2,3), (4,5,6) and (5,6,7). These components are in kgms^(-1) . If the velocity of centre of mass of the system is (30,39,48)ms^(-1) , then find the total mass of the system.