In `DeltaABC, angleC=angleA, BC=4cm and AC=5cm.` Then, AB = ?

In DeltaABC,angleABC=angleDAC , AB = 8 cm, AC = 4 cm and AD = 5 cm. (ii) Find the length of BC and CD.

In DeltaABC , If angleC=90^(@), angleA=60^(@) and AB=40 cm , then AC is equal to

In DeltaABC, angleB=angleC. If AB = 8 cm and if the line segment through D, the mid-point of AB and parallel to BC intersects AC at E, then CE =

Draw DeltaABC , AB=AC=4cm, BC=6cm

In DeltaABC , angleA is right - angled . If AB= 1 cm , AC =3 cm and BC = sqrt(10) cm , then find the values of cos B and sin C.

In DeltaABC , angleA is right - angled . If AB= 1 cm , AC =3 cm and BC = sqrt(10) cm , then find the values of cos B and sin C.

In a DeltaABC, angleA=60^@ , AB = 3 cm , AC = 4 cm .Find the length of AD, if it is angle bisector.

IN DeltaABC AD bisects angleA . AB=6cm, BD=8cm and DC=6cm then AC=………..cm.

In DeltaABC , angleA=30^@ , angleB=90^@ , angleC=60^@ , AC=18. Then find AB and BC.