A cell with `N//50` KCl solution offered a resistance of 550 ohm at 298 K. The specific conductance of `N//50` KCl at 298 K is 0.002768 `ohm^(-1)cm^(-1)`. When this cell is filled with `N//10 ZnSO_(4)` solution, it offered a resistance of 72.18 ohm at 298 K. Find the cell constant and molar conductance of `ZnSO_(4)` solution at 298 K.

At 18^(@)C , the specific conductance of (N/10) KCl solution is "0.0112 ohm"^(-1)."cm"^(-1) . When a conductivity cell is filled with that solution, the resistance of the cell stands at 55 ohm. What is the cell constant of the cell?

The specific conductance of a 0.1 N KCl solution at 23^(@)C is 0.012 ohm^(-1) cm^(-1) . The resistance of cell containing the solution at the same tempreature was found to be 55 ohm . The cell constant will be

The specific conductance of a 0.1 N KCl solution at 23^(@)C is 0.012 "ohm"^(-1)"cm"^(-1) . The resistance of the cell containing the solution at the same temperature was found to be 55 ohm. The cell constant will be

A conductivity cell was filled with 0.01 M solution of KCl which was known to have a specific conductivity of 0.1413 ohm^(-1) m^(-1) at 298 K. Its measured resistance at 298 K was 94.3 ohm. When the cell was filled with 0.02 M AgNO_(3) solution, its resistance was 50.3 ohm. Calculate (i) cell constant and (ii) the specific conductance of AgNO_(3) solution.

Resistance is 82.3 ohm, when a conductivity cell is filled with 0.02 (N) KCl solution at a definite temperature. At the same temperature, the specific conductance of 0.02 (N) KCl solution is "0.002758 ohm.cm"^(-1) . The resistance is 324 ohm when the cell is filled with :0.05 (N)K_(2)SO_(4) solution. Calculated the equivalent and molar conductivity of K_(2)SO_(4) solution.