The value of parameter `alpha`, for which the function `f(x) = 1+alpha x, alpha!=0` is the inverse of itself

The value of parameter alpha , for which the function f(x) =1+alphax, alpha ne 0 is the inverse of itself is:

The value of the parameter alpha for which the function f(x)=1+alphax,alphane0 , is the inverse of itself is :

The value of alpha(ne0) for which the function f(x)=1+alphax is the inverse of itself is :

the value of alpha (ne 0) for which the function f(x ) = 1+ ax is the inverse of itself is :

Find the complete set of values of alpha for which the function f(x) = {(x+1,xlt1 alpha , x =1 , is strictly increasing x=1 x^(2)-x+3,xlt1

Find the complete set of values of alpha for which the function f(x) = {(x+1,xlt1 alpha , x =1 , is strictly increasing x=1 x^(2)-x+3,xgt1

Find the complete set of values of alpha for which the function f(x) = {(x+1,xlt1 alpha , x =1 , is strictly increasing x=1 x^(2)-x+3,xlt1

Let [x] denote the greatest integer less than or equal to x . Then the value of alpha for which the function f(x)={(sin[-x^2]/[x^2),xne0),(alpha, x=0):} is continuous at x=0 is