A thin lens made of glass of refractive index `muu = 1.5` has a focal length equal to 12 cm in air. It is now immersed in water (`mu=4/3`). Its new focal length is

A thin lens made of glass of refractive index mu = 1.5 has a focal length equal to 12 cm in air. It is now immersed in water ( mu=4/3 ). Its new focal length is

A thin lens of focal length + 12 cm is immersed in water (mu = 1.33). What is its new focal length ?

A thin lens of focal length + 12 cm is immersed in water (mu = 1.33). What is its new focal length ?

A thin lens of focal length + 12 cm is immersed in water (mu = 1.33). What is its new focal length ?

A convex lens made of a glass of refractive index 3//2 has a focal length 'f' in air. If it is immersed into water of refractive index 4//3 , then with calculation, predict the new focal length of the lens inside water.

A thin lens of refractive index 1.5 has focal length of 15 cm in air. When the lens is placed is a medium of refractive index (4)/(3), its focal length will become …..cm.

A thin lens of refractive index 1.5 has focal length of 15 cm in air. When the lens is placed is a medium of refractive index (4)/(3), its focal length will become …..cm.

A thin convex lens which is made of glass (refractive index 1.5) has a focal length of 20 cm. It is now completely immersed in a transparent liquid having refractive index 1.75. Find the new focal length of the lens.