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cos((dy)/(dx))=a(a inR),y=1 यदि x = 0...

`cos((dy)/(dx))=a(a inR),y=1` यदि x = 0

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cos((dy)/(dx))=a(a in R);y=1 when x=0

cos ((dy)/(dx))=a, (a in R) , y=1 , when x=0

cos ((dy)/(dx)) = a (a ne R), y = 1 when x = 0

cos ((dy)/(dx)) = a (a ne R), y = 1 when x = 0

cos^(-1)((dy)/(dx))=x+y

cos(x+y)dy=dx

(dy)/(dx)=cos(x+y)

(dy)/(dx)=cos(x-y)

(6) (dy)/(dx)cos(x+y)=1