A uniform bar of length 2 m and cross-sectional area `50cm^(2)` is subjected to a tensile load 100 N. If Young's modulus of material of bar is `2xx10^(7)N//m^(2)` and poisson's ratio is 0.4, then determine the volumetric strain.

The Young's modulus of a material is 10^(11)N//m^(2) and its Poisson's ratio is 0.2 . The modulus of rigidity of the material is

Bulk modulus of a material is 2.5xx10^(11)"dyne"//cm^(2) and Poisson's ratio is 0.4. Then young's modulus for such material ios

A uniform wire of length 6m and a cross-sectional area 1.2 cm^(2) is stretched by a force of 600N . If the Young's modulus of the material of the wire 20xx 10^(10) Nm^(-2) , calculate (i) stress (ii) strain and (iii) increase in length of the wire.

If bulk modulus of the metal is 2xx10^(12)Pa and Poisson's ratio is 0.4 then young's modulus of the metal is

A unifrom bar of Length 'L' and cross sectional area 'A' is subjected to a tesnile load 'F', 'Y' be the Young's modulus and 'sigma' be the Poisson's ratio then volumeteric strain is

Work done in stretching a wire of length 1 m and of cross-sectional area 1 mm^(2) through 2 mm if Young's modulus of the material of the wire is 2 xx 10 ^(11) N//m^(2) is .......

The Young's modulus of the material of a wire is 6 xx 10^(12) N//m^(2) and there is no transverse strain in it.then it modulus of rigidity will be

A elongation of 0.1% in a wire of cross-sectional area 10"6 m2 causes tension 100 N. The young’s modulus is

A uniform rod of length (L) and area of cross-section (A) is subjected to tensil load (F). If sigma be the Poisson's ratio and Y be the Young's modulus of the material of the rod, then find the volumetric strain produced in the rod.

A copper wire of length 4.0 mm and area of cross-section 1.2 cm^(2) is stretched with a force of 4.8 xx 10^(3) N. If Young's modulus for copper is 1.2xx10^(11) N//m^(2) , the increases in the length of the wire will be