If `z= (cos theta, sin theta)`, find `(z-(1)/(z))`

If n is an integer and z=cos theta+i sin theta , then (z^(2 n)-1)/(z^(2 n)+1)=

If z_1 = cos theta + i sin theta and 1,z_1,(z_1)^2,(z_1)^3,.....,(z_1)^(n-1) are vertices of a regular polygon such that (Im(z_1)^2)/(Re Z_1) = (sqrt5-1)/2 , then the value n is

If z=(1)/(1-cos theta-i sin theta), then Re(z) is a.0 b.(1)/(2) c.cot((theta)/(2)) d.(1)/(2)cot((theta)/(2))

If z=1/(1-cos theta-i sin theta), then Re(z) is a. 0 b. 1/2 c. cot(theta/2) d. 1/2 cot (theta/2)

z=i+sqrt(3)=r(cos theta+sin theta)

If z = 1 - cos theta + i sin theta , then |z| =

If z = (1)/(1 - cos theta - i sin theta), the Re (z)=

If z= r (cos theta + i sin theta) , then the value of (z)/(bar(z)) + (bar(z))/(z) is

If z = (1+cos theta + i sin theta)/(sin theta + i(1+cos theta))(0 lt theta lt pi//2) then |z| equals