The function `f:N->N` defined by `f(x)=x-5[x/5]` where N is a set of natural numbers, then

The function f : N to N defined f(x) = a+bx, where a and b are natural numbers is

The mapping f:NrarrN given by f(n)=1+n^(2), n in N where N is the set of natural numbers, is

If f:N rarr N is defined by f(x)=2x+5 then f is

The function f : N rarr N , Where N is the set of natural numbers, defined by f(x) = 3x+4 is

Define a function f:R rarr R by f(x)=max{|x|,|x-1|,...|x-2n|} where n is a fixed natural number then int_(0)^(2n)f(x)dx is

Show that the function f: N rarr N defined by f(x)= 2x + 3 , where x in N , is not bijective.

Let N be the set of Natural numbers. Consider the function f:NtoN defined by f(x)=x+1, x in N Check whether f is an onto function.