Calculate the diameter of one molecule of an ideal gas having number density `2xx10^(8) cm^(-3)` and mean free path of the molecule is `10^(-8)` cm.

Mean free path of a gas molecule is

Mean free path of a gas molecule is :

Calculate the mean free path of molecule of a gas having number density (number of molecules per cm^3 ) 2xx10^(8) and the diameter of the molecule is 10^(-5) cm.

Calculate the number of molecules per cc of a gas if the diameter of molecules of gas is 2xx10^(-10) m and the mean free path of the molecules of the gas is 2.4xx10^(-9) m.

Calculate themean free path of molecule of a gas having number density (number of molecules per cm^(3) ) 2xx10^(8) and the diameter of the molecule is 10^(-5) cm

Calculate themean free path of molecule of a gas having number density (number of molecules per cm^(3) ) 2xx10^(8) and the diameter of the molecule is 10^(-5) cm

For a molecule of an ideal gas n=3xx10^(8)cm^(-3) and mean free path is 10^(-2) cm. Calculate the diameter of the molecule.