A U-tube of uniform cross-sectional area and open to the atmosphere is partially filled with mercury. Water is then poured into both arms. If the equilibrium configuration of the tube is as shown in figure with `h_(2)=1.0cm`, determine the value of `h_(1)`
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Fig, shows a U-tube of uniform cross-sectional area A accelerated with acceleration a as shown. If d is the seperation between the limbs. Then the difference in the levels of the liquid in the U-tube is

A tube 1 cm^2 in cross- section is attached to the top of a vessel 1 cm high and of cross - section 100 cm^2 Water is poured into the system filling it to a depth of 100 cm above the bottom of the vessel as shown in fig. Take g =10 ms^(-2) .

A tube 1 cm^2 in cross- section is attached to the top of a vessel 1 cm high and of cross - section 100 cm^2 Water is poured into the system filling it to a depth of 100 cm above the bottom of the vessel as shown in fig. Take g =10 ms^(-2) .

An open U-tube contains mercury. When 11.2 cm of water is poured into one of the arms of the tube, how high does the mercury rise in the other arm from its initial level ?

An open U-tube contains mercury. When 11.2 cm of water is poured into one of the arms of the tube, how high does the mercury rise in the other arm from its initial level ?

An open U-tube contains mercury. When 11.2 cm of water is poured into one of the arms of the tube, how high does the mercury rise in the other arm from its initial level ?

The cross-sectional area and length of each arm of a U-tube are 1cm^(2) and 33 cm respectively. Mercury is poured into it up to a height of 6.8 cm in each arm. Now water is poured into one of the arms to fill it completely. If the density of mercury is 13.6g*cm^(-3) , then determine the volume of water poured into it.

A tube of uniform cross section is used to siphon water from a vessel V as shown in the figure. The pressure over the open end of water in the vessel is atmospheric pressure (P_(0)) . The height of the tube above and below the water level in the vessel are h_(1) and h_(2) , respectively. Given h_(1) = h_(2) = 3.0 m , the gauge pressure of water in the highest level CD of the tube will be

A tube of uniform cross section is used to siphon water from a vessel V as shown in the figure. The pressure over the open end of water in the vessel is atmospheric pressure (P_(0)) . The height of the tube above and below the water level in the vessel are h_(1) and h_(2) , respectively. Given h_(1) = h_(2) = 3.0 m , the gauge pressure of water in the highest level CD of the tube will be