`sin42^(@)*cos48^(@)+cos42^(@)*sin48^(@)` का मान निकालें।

sin42^(@)sec48^(@)+cos42^(@)cos ec48^(@)=2

sin48^(@)sec42^(@)+cos48^(@)csc42^(@)=

(sin48^(@))/(cos42^(@))+(cos48^(@))/(sin42^(@))=2

(sin9^(@)-cos9^(@))/(sin48^(@)sin 12^(@))=

Evaluate: sin 42^(@)sin 48^(@)-cos 42^(@)cos 48^(@)

cos^(2)48^(@)-sin^(2)12^(@)=?

cos48^(@)cos23^(@)cos ec42^(@)cos ec67^(@)=1

((sin48^(@))/(cos42^(@)))+((cos48^(@))/(sin42^(@)))=2

Show that : (i) tan 10^(@) tan 15^(@) tan 75^(@) tan 80^(@) = 1 (ii) sin 42^(@) sec 48^(@) + cos 42^(@) "cosec 48"^(@) = 2

Evaluate: cos48^(@)-sin42^(@)