In an experiment to measure the internal resistance of a cell by a potentiometer, it is found that the balance point is at a length of `2 m` when the cell is shunted by a `5 Omega` resistance and is at a length of `3 m` when the cell is shunted by a `10 Omega` resistance, the internal resistance of the cell is then

In an experiment to measure the internal resistance of a cell by potentiometer, it is found that the balance point is at a length of 2 m when the cell is shuntedd by a 5 Omega resistance, and is at a length of 3 m when the cell is shunted by a 10 Omega resistance. The internal resistance of the cell is, then

In an experiment to measure the internal resistance of a cell by potentiometer, it is found that the balance point is at a length of 2 m when the cell is shuntedd by a 5 Omega resistance, and is at a length of 3 m when the cell is shunted by a 10 Omega resistance. The internal resistance of the cell is, then

In an experiment to measure the internal resistance of a cell by potentiometer, it is found that the balance point is at a length of 2 m when the cell is shunted by a 4Omega resistance and at 3 m when cell is shunted by a 8Omega resistance. The internal resistance of cell is -

In an experiment to measure the internal resistance of a cell by potentiometer, it is found that the balance point is at a length of 2 m when the cell is shunted by a 4Omega resistance and at 3 m when cell is shunted by a 8Omega resistance. The internal resistance of cell is -

In an experiment with potentiometer to measure the internal resistance of a cell when the cell is shunted by 5Omega the null point is obtained at 2m .When the cell is shunted by 10Omega the null point is obtained at 3m .The internal resistance of the cell is

In a potentiometer experiment, e.m.f. of a cell is balanced by a length of 150 cm on the potentiometer wire. When the cell is shunted by a 10 Omega resistance, the balancing length reduces to 90 cm. What is the internal resistance of the cell?

In an experiment to find the internal resistance of a cell by a potentiometer, a balance was obtained for 50 cm length of the potentiometer wire, with a cell of e.m.f. 2V. When the cell was shunted by a resistance of 2 Omega , the balancing length of the potentiometer wire was 40 cm. What was the internal resistance of the cell ?

In an experiment with potentiometer to measure the internal resistance of a cell, when the cell is shunted by 5Omega , the null point is obtained at 2m. when cell is shunted by 20Omega the null point is obtained at 3m. The internal resistance of cell is

In an experiment to determine the internal resistance of a cell, the null point is obtained at 2 cm, when the cell is shnted by a resistance of 5Omega . When the cell is shunted by a resistance of 20Omega , the null point is obtained at 3 cm. Find the internal resistance of the cell.