`1-log_(e) 2=1/2.3+1/4.5+1/6.7+...oo` पद तक

If x = (1)/(1.2) + (1)/(3.4) + (1)/(5.6) …….oo, and y = 1 - (1)/(2.3) - (1)/(4.5) - (1)/(6.7)…….oo , then

If x = (1)/(1.2) + (1)/(3.4) + (1)/(5.6) …….oo, and y = 1 - (1)/(2.3) - (1)/(4.5) - (1)/(6.7)…….oo , then

Prove that, 1/(2.3)-1/(4.5)+1/(6.7)+.....=1-log_e2

(1+2/3+6/3^2+10/3^3+. . . + oo)^(log_(0.25)(1/3+1/3^2+1/3^3+. . . +oo)) is equal L and then find L^2

Show that, log_e2=1/(1.2)+1/(3.4)+1/(5.6)+.....infty

1+(log_(e)5)/(1!) +(log_e5)^2/(2!)+(log_e5)^3/(3!)+ .......oo =