when the maximum k.E of a simple pendulum is k, then what is its displacement in terms of amplitude a when its K.E. is `k//2`

The total energy of a simple pendulum is x. When the displacement is half of amplitude,its KE will be

The total energy of a simple pendulum is x. When the displacement is half of amplitude,its KE will be

The angular velocity and the amplitude of a simple pendulum is omega and A respectively. At a displacement x from the mean position if its kinetic energy is k and potential energy U, then the ratio of K and U is………..

A particle is performing S.H.M. Its total energy ie E When the displacement of the particle is half of its amplitude, its K.E. will be

A particle is performing S.H.M. Its total energy ie E When the displacement of the particle is half of its amplitude, its K.E. will be

At which position the bob of simple pendulum has maximum K.E.?

A pendulum is executing simple harmonic motion and its maximum kinetic energy is K_(1) . If the length of the pendulum is doubled and it perfoms simple harmonuc motion with the same amplitude as in the first case, its maximum kinetic energy is K_(2) Then:

A pendulum is executing simple harmonic motion and its maximum kinetic energy is K_(1) . If the length of the pendulum is doubled and it perfoms simple harmonuc motion with the same amplitude as in the first case, its maximum kinetic energy is K_(2) Then: