Let `f(x) = {{:(-1,-2 le x lt 0),(x^2-1,0 le x le 2):}` and `g(x)=|f(x)|+f(|x|)`. Then , in the interval (-2,2),g is

Let f(x) be defined on [-2,2[ such that f(x)={{:(,-1,-2 le x le 0),(,x-1,0 le x le 2):} and g(x)= f(|x|)+|f(x)| . Then g(x) is differentiable in the interval.

Let f(x) be defined on [-2,2] and is given by f(x)={{:(,-1,-2 le x le 0),(,x-1,0 lt x le 2):} and g(x) =f(|x|)+|f(x)| . Then g(x) is equal to

Let f(x) be defined on [-2, 2] and be given by f(x)= {:{(-1,-2 le x le0),(x-1,0 lt 2 le 2):} and g(x)=f(|x|)+|f(x)| , Then find g(x)

Let f(x) be defined on [-2,2] and be given by f(x)={(-1",",-2 le x le 0),(x-1",",0 lt x le 2):} and g(x)=f(|x|) +|f(x)| . Then find g(x) .

Let f(x) be defined on [-2,2] and be given by f(x)={(-1",",-2 le x le 0),(x-1",",0 lt x le 2):} and g(x)=f(|x|) +|f(x)| . Then find g(x) .

Let f(x) be defined on [-2,2] and be given by f(x)={(-1",",-2 le x le 0),(x-1",",0 lt x le 2):} and g(x)=f(|x|) +|f(x)| . Then find g(x) .

Let f(x) be defined on [-2,2] and be given by f(x)={(-1",",-2 le x le 0),(x-1",",1 lt x le 2):} and g(x)=f(|x|) +|f(x)| . Then find g(x) .

Let f(x) be defined on [-2,2] and be given by f(x)={(-1",",-2 le x le 0),(x-1",",1 lt x le 2):} and g(x)=f(|x|) +|f(x)| . Then find g(x) .

Let f(x)={{:(1+x",", 0 le x le 2),(3-x"," ,2 lt x le 3):} find (fof) (x).