Ethanol `(C_(2)H_(5)OH`, M=46) and methanol `(CH_(3)OH,` M= 32) form an ideal solution when mixed. What is the vapour pressure of a solution prepared by mixing equal masses of ethanol and methanol ? (The vapour pressure of ethanol and methanol are 44.5 mm Hg and 88.7 mm Hg, respectively.)

Methanol (p^@"=90 mm Hg at 300 K") and ethanol (p^@="51 mm Hg at 300 K") form very nearly an ideal solution. The total vapour pressure of a solution obtained by mixing 23 g ethanol with 32g methanol would be

An ideal solution was obtained by mixing methanol and ethanol. If the partial vapour pressure of methanol and ethanol are 2.619 kPa and 4.556 kPa , respectively, the composition of vapour (in terms of mole fraction) will be

An ideal solution was obtained by mixing methanol and ethanol. If the partial vapour pressure of methanol and ethanol are 2.619 kPa and 4.556 kPa , respectively, the composition of vapour (in terms of mole fraction) will be

An ideal solution was obtained by mixing methanol and ethanol. If the partial vapour pressure of methanol and ethanol are 2.619 kPa and 4.556 kPa , respectively, the composition of vapour (in terms of mole fraction) will be

The vapour pressure of ethanol (C_(6)H_(5) OH) and methanol (CH_(3) OH) are 44.5 and 88.7 mm Hg respectively. An ideal solution is formed at the same temperature by mixing 60 g of ethanol and 40 g methanol (i) Calculate the total vapour pressure of the solution (ii) Find mole fraction of each component in vapour phase

An ideal solution was obtained by mixing methanol and ethanol. If the partial vapour pressure of methanol and ethanol are 2.619 KP_a and 4.556 KP_a respectively, the composition of vapour ( in terms of mole fraction) will be:

No solution with a vapour pressure can be prepare when nonvolatile solute is added in a pure solvent having vapour pressure in equal to 520 mm of Hg

1 mole heptane (V.P = 92 mm of Hg) is mixed with 4 mol. Octane (V.P = 31 mm of Hg) , form an ideal solution. Find out the vapour pressure of solution.