The power of black body at temperature 200 K is 544 W .Its surface area is
`(sigma=5.67xx10^(-8)Wm^(-2)K^(-2))`

The power of a black body at temperature 200K is 544 watt. Its surface area is (sigma = 5.67 xx 10^(-8) wm^(-2) K^(-4))

Calculate the amount of radiant energy from a black body at a temperature of (i) 27^(@) C (ii) 2727^(@) C. sigma = 5.67xx10^(-8)Wm^(-2)K^(-4) .

Calculate the power of an incandescent lamp whose filament has a surface area of 0.19 cm^(2) and is at a temperature of 3645K. Emmisivity of the surface is 0.4, sigma = 5.7xx10^(-8)Wm^(-2)K^(-4) ?

The temperature of a perfect black body is 1 000K and its area is 0.1 m^(2) . If sigma = 5.67 xx 10^(-8) W m^(-2) K^(-4) calculate the heat radiated by it in 1 minute ?

Calculate the temperature (in K) at which a perfect black body radiates energy at the rate of 5.67W cm^(-2) . Given sigma = 5.67 xx 10^(8)Wm^(-2)K^(-4) .

How much energy will be emitted from a furnace at 3000K temperature active as a perfect black body per unit area in 1 hour ? (sigma=5.7xx10^(-8)" Wm"^(-2)K^(-4))

The earth receives solar energy at the rate of 2 cal Cm^(-2) per minute. Assuming theradiation tobeblack body in character, estimate the surface temperature of the sun. Given that sigma =5.67 xx10^(-8) Wm^(-2)K^(-4) and angular diameter of the sun =32 minute of arc.