If the radius of `Cs^(+)` si `169p m` and that of `Cl^(-)` is `181 p m`, then find the co`-` ordination number of `Cs^(+)`

If the radius of Na^(+) ion is 95 p m and that of Cl^(-) ion is 181 p m , then :

If the radius of Na^(+) ion is 95 p m and that of Cl^(-) ion is 181 p m , then :

If the radius of Na^(+) ion is 95 p m and that of Cl^(-) ion is 181 p m , then the coordination number if of Na+

The radius of the Na^(2+) is 95p m and that of Cl^(-) ion is 181 p m . Predict the co - ordination number of Na^(+) :

The radius of Na^(+) is 95 pm and that of CI^(-) ion is 181 pm. Hence the co-ordination number of Na^(+) will be

In h.c.p arrangement, the co-ordination number is

The radius of Cs^(+) ion is 160pm while the radius of Cl^(-) ion is 181pm . Suggest the co - ordination of cesium in CsCl .

The radius of Na^(+) ion is 95 pm and that of Cl^(-) ion is 181 pm. Predict the structure of Na^(+)Cl^(-) and the coordination number of cation.

The atomic radii of Cs^(+) and Cl^(-) ions are 1.69 Å and 1.81 Å respectively. Predict the coordination number of Cs^(+) ion and structure of CsCl.