`logx=y` হলে `x^2frac[d^2y][dx^2]`-এর মান কত হবে ?

dy/dx = frac{x^2+y^2}{2x^2}

if y=xcosx , find frac(d^2y)(dx^2)

Mention the order and the degree of the differential equations x^2+frac(d^2y)(dx^2)- xy dy/dx = y

dy/dx = frac{2x+y}{x}

Find frac(d^2y)(dx^2) : (v) sin x + cos y = 1

Find (d^2y)/dx^2 , if y = logx

Find frac(d^2y)(dx^2) : (i) x^2/a^2+y^2/b^2 = 1

Write the order and degree of the differential equation frac[dy][dx]= [1+(frac[d^2y][dx^2])^2]^(frac[2][3]

x dy/dx+y=y^2 logx