A block is released from top of a smooth inclined plane It reaches the bottom of the plane in `sqrt2s` The time taken (in second) by the body to cover Ist half of inclined plane is .

A block is released from top of a smooth inclined plane.It reaches the bottom of the plane in 6 sec.The time taken by the body to cover the first half of the inclined plane is:

A block of mass m is released from the top of a mooth inclined plane of height h its speed at the bottom of the plane is proportion to

A block is released from the top of the smooth inclined plane of height h . Find the speed of the block as it reaches the bottom of the plane.

A block released from rest from the top of a smooth inclined plane of angle theta_1 reaches the bottom in time t_1 . The same block released from rest from the top of another smooth inclined plane of angle theta_2 reaches the bottom in time t_2 If the two inclined planes have the same height, the relation between t_1 and t_2 is

A block released from rest from the top of a smooth inclined plane of angle theta_1 reaches the bottom in time t_1 . The same block released from rest from the top of another smooth inclined plane of angle theta_2 reaches the bottom in time t_2 If the two inclined planes have the same height, the relation between t_1 and t_2 is

A small block is freely sliding down from top of a smooth inclined plane. The block reaches bottom of inclined plane then the block describes a vertical circle of radius 0.5 m along smooth track. The minimum vertical height of inclined plane should be