In a conductivity cell the two platinum electrodes each of area 10 sq. cm are fixed 1.5 cm apart. The cell. Contained `0.05N` solution of a salt. If the two electrodes are just half dipped into the solution which has a resistance of 50 ohms, find equivalent conductance of the salt solution.

In a conductivity ecll the two patinum electrodes, each of area 10 sq . Cm si fixed 1.5 cm apart . The cell contained 0.05 N solution of a salt. If the two electrodes are just half dipped into the solution which has a resistance of 50 Omega , find equivalent conductance of the salt solution .

0.5 N solution of a salt placed between two platinum electrode 2.0cm apart and of area of cross-secton 4.0 sq. cm has a resistance of 25 ohms. Calculate the equivalent conductance of solution.

A conductivity cell has two electrodes 50 mm apart and of cross section area 2.5 cm^2 . Find the cell constant.

0.5 N solution of an electrolyte placed between two platinum electrodes 2.0 cm apart and area of cross section 4.0 sq. cm has a resistance of 250 ohm . Calculate the equivalent conductance of the solution.

1.0 N solution of a salt surrounding two platinum electrodes 2.1 cm apart and 4.2 sq cm in area was found to offer a resistance of 50 ohm. Calculate the equivalent conductivity of the solution.

A conductance cell has platinum electrodes, each with 5 cm^(2) area and separated by 0.5 cm distance. What is the cell constant?

A conductance cell has platinum electrodes, each with 5 cm^(2) area and separated by 0.5 cm distance. What is the cell constant?