The equation to sphere passing throrugh origin and the points (-1,0,0),(0,-2,0) and (0,0,-3) is `x^2+y^2+z^2+f(x,y,z)=0`. What if f(x,y,z) equal to ?

The equations to sphere passing through origin and the points (-1,0,0),(0,-2,0) and (0,0,-3) is x^2+y^2+z^2+f(x,y,z)=0 . What is f(x,y,z)=

The equation of the plane passing through the intersection of x+2y+3x+4=0 and 4x+3y+2z+1=0 and the origin (0.0,0) is

The equation of the plane passing through the intersection of x + 2y + 3z + 4 = 0 and 4x + 3y + 2z+ 1 = 0 and the origin (0.0, 0) is

The equation of the plane thorugh the point (-1,2,0) and parallel to the lines x/3=(y+1)/0=(z-2)/(-1) and (x-1)/1=(2y+1)/2=(z+1)/(-1) is (A) 2x+3y+6z-4=0 (B) x-2y+3z+5=0 (C) x+y-3z+1=0 (D) x+y+3z-1=0

The equation of the plane thorugh the point (-1,2,0) and parallel to the lines x/3=(y+1)/0=(z-2)/(-1) and (x-1)/1=(2y+1)/2=(z+1)/(-1) is (A) 2x+3y+6z-4=0 (B) x-2y+3z+5=0 (C) x+y-3z+1=0 (D) x+y+3z-1=0

The equation of the plane passing through the intersection of x + 2y + 3x + 4 = 0 and 4x + 3y + 2z+ 1 = 0 and the origin (0.0, 0) is

The equation of the plane passing through the intersection of x + 2y + 3x + 4 = 0 and 4x + 3y + 2z+ 1 = 0 and the origin (0.0, 0) is

Let (x,y,z) be an arbitrary point lying on a plane P which passes through the points (42,0,0), (0,42,0) and (0,0,42), then the value of the expression 3+(x-11)/((y-19)^(2)(z-12)^(2))+(y-19)/((x-11)^(2)(z-12)^(2))+(z-12)/((x-11)^(2)(y-19)^(2))-(x+y+z)/(14(x-11)(y-19)(z-12)) is equal to :

The equation of the plane passing through the line of intersection of the planes x+y+z+3 =0 and 2x-y + 3z +2 =0 and parallel to the line (x)/(1) = (y)/(2) = (z)/(3) is

If the origin and the point P(2,3,4),Q(,1,2,3)R (x,y,z) are coplanar then: a) x-2y-z=0 b) x+2y+z=0 c) x-2y+z=0 d) 2x-2y+z=0