Two particles are executing SHM in a straight line. Amplitude A and the time period T of both the particles are equal. At time t=0, one particle is at displacement `x_(1)=+A` and the other `x_(2)=(-A/2)` and they are approaching towards each other. After what time they across each other? `T/4`

Two particles are in SHM in a straight line about same equilibrium position. Amplitude A and time period T of both the particles are equal. At time t=0 , one particle is at displacement y_(1)=+A and the other at y_(2)=-A//2 , and they are approaching towards each other. after what time they cross each other?

Two particles are in SHM in a straight line about same equilibrium position. Amplitude A and time period T of both the particles are equal. At time t=0 , one particle is at displacement y_(1)=+A and the other at y_(2)=-A//2 , and they are approaching towards each other. after what time they cross each other?

Two particle executing SHM along a straight linehave same amplitude A and time period T. At t=0 one particle is at a displacement +A and another is at a displacement -A//2 and they are approaching towards each other. They cross each other after a tme.