A ball is thrown vertically up with a certain velocity. It attains a height of `40m` and comes back to the thrower. Then the `(g=10m//s^(2))`

A ball is thrown vertically up with a certain velocity. It attains a height of 40 m and comes back to the thrower. Then the : (g = 10 m//s^(2)) .

A ball is thrown vertically upward with a velocity of 20 m/s. Calculate the maximum height attain by the ball.

A ball is thrown vertically upward with a velocity of 20 m/s. Calculate the maximum height attain by the ball.

From the top of a tower of height 50m, a ball is thrown vertically upwards with a certain velocity. It hits the ground 10 s after it is thrown up. How much time does it take to cover a distance AB where A and B are two points 20m and 40m below the edge of the tower ? (g= 10ms^(-2))

From the top of a tower of height 50m, a ball is thrown vertically upwards with a certain velocity. It hits the ground 10 s after it is thrown up. How much time does it take to cover a distance AB where A and B are two points 20m and 40m below the edge of the tower ? (g= 10ms^(-2))

A particle is thrown vertically upward. Its velocity at half of the height is 10 m/s. Then the maximum height attained by it : - (g=10 m//s^2)

A particle is thrown vertically upwards its velocity at half of the height is 10 m/s then the maximum height attained by it is ( g= 10 m//s^2)

A particle is thrown vertically upward. Its velocity at half of the height is 10 m/s. Then the maximum height attained by it : - (g=10 m//s^2)

If a ball is thrown vertically upwards with a velocity of 40m//s , then velocity of the ball after 2s will be (g = 10m//s^(2)) (a) 15m//s (b) 20 m//s (c) 25m//s (d) 28 m//s