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if a+b+c=0 then Delta=|{:(a-x,c,b),(c,b-...

if `a+b+c=0` then `Delta=|{:(a-x,c,b),(c,b-x,a),(b,a,c-x):}|=0` is

A

1

B

`-1`

C

`a^(2)+b^(2)+c^(2)`

D

0

Text Solution

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The correct Answer is:
D
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