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The two points A and B in a plane are su...

The two points `A` and `B` in a plane are such that for all points `P` lies on circle satisfied `PA/PB=k` , then `k` will not be equal to

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The two points A and B in a plane are such that for all points P lies on circle satisfied P(A)/(P)B=k, then k will not be equal to

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Knowledge Check

  • PA and PB are two tangents to a circle with centre O, from a point P outside the circle . A and B are point P outside the circle . A and B are point on the circle . If angle PAB = 47^(@) , then angle OAB is equal to :

    A
    `43^(@)`
    B
    `53^(@)`
    C
    `50^(@)`
    D
    `20^(@)`

  • PA and PB are tangents to a circle with centre O, from a point P outside the circle and A and B are points on the circle. If /_ APB = 30^(@) , then /_ OAB is equal to :

    A
    A) `40^(@)`
    B
    B) `15^(@)`
    C
    C) `50^(@)`
    D
    D) `25^(@)`

  • From a point P outside the circle with centre O, two tangents PA and PB are drawn to meet the circle at A and B respectively. If /_APB = 70^@ , then /_OAB is equal to:

    A
    `35^@`
    B
    `65^@`
    C
    `45^@`
    D
    ` 55^@`

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    The coordinates of the point A and B are (a,0) and (-a,0), respectively.If a point P moves so that PA^(2)-PB^(2)=2k^(2), when k is constant,then find the equation to the locus of the point P.

    Statement 1: let A( vec i+ vec j+ vec k)a n dB( vec i- vec j+ vec k) be two points. Then point P(2 vec i+3 vec j+ vec k) lies exterior to the sphere with A B as its diameter. Statement 2: If Aa n dB are any two points and P is a point in space such that vec P Adot vec P B >0 , then point P lies exterior to the sphere with A B as its diameter.

    PA and PB are two tangents to a circle with centre O, from a point P outside the circle. A and B are points on the circle. If /_APB = 40^@ , then /_OAB is equal to:

    PA and PB are two tangents to a circle with centre O, from a point P outside the circle. A and B are points on the circle. If angleAPB =100^(@) , then OAB is equal to:

    PA and PB are tangents to a circle with centre 0, from a point P outside the circle, and A and B are point on the circle. If angleAPB = 30^(@) , then angleOAB is equal to:

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