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P is a point on the circle x^2+y^2=9 Q i...

P is a point on the circle `x^2+y^2=9` Q is a point on the line `7x+y+3=0`. The perpendicular bisector of PQ is `x-y+1=0`. Then the coordinates of P are:

A

`(3,0)`

B

`(0,3)`

C

`(-72,21)`

D

`(-1,1)`

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The correct Answer is:
A
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