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The length of the longest ray drawn from...

The length of the longest ray drawn from the point (4,3) to the circle `x ^(2) + y ^(2) + 16 x + 18y + 1=0` is equal to

A

the radius of the circle

B

the diameter of the circle

C

circumference of the circle

D

the distance of the centre of the cirlce from the origin

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To find the length of the longest ray drawn from the point (4,3) to the circle given by the equation \(x^2 + y^2 + 16x + 18y + 1 = 0\), we can follow these steps: ### Step 1: Rewrite the Circle Equation First, we need to rewrite the equation of the circle in standard form. The given equation is: \[ x^2 + y^2 + 16x + 18y + 1 = 0 \] We can rearrange it as: \[ x^2 + 16x + y^2 + 18y = -1 \] Now, we complete the square for both \(x\) and \(y\). ### Step 2: Completing the Square For \(x^2 + 16x\): \[ x^2 + 16x = (x + 8)^2 - 64 \] For \(y^2 + 18y\): \[ y^2 + 18y = (y + 9)^2 - 81 \] Substituting these back into the equation gives: \[ (x + 8)^2 - 64 + (y + 9)^2 - 81 = -1 \] Simplifying this leads to: \[ (x + 8)^2 + (y + 9)^2 - 145 = 0 \] Thus, we have: \[ (x + 8)^2 + (y + 9)^2 = 145 \] This shows that the circle has a center at \((-8, -9)\) and a radius of \(\sqrt{145}\). ### Step 3: Calculate the Distance from the Point to the Center Next, we need to find the distance from the point (4, 3) to the center of the circle \((-8, -9)\). The distance \(d\) can be calculated using the distance formula: \[ d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2} \] Substituting the coordinates: \[ d = \sqrt{(4 - (-8))^2 + (3 - (-9))^2} \] This simplifies to: \[ d = \sqrt{(4 + 8)^2 + (3 + 9)^2} = \sqrt{12^2 + 12^2} = \sqrt{144 + 144} = \sqrt{288} \] Thus, \(d = 12\sqrt{2}\). ### Step 4: Find the Length of the Longest Ray The length of the longest ray drawn from the point (4, 3) to the circle is equal to the distance from the point to the center of the circle plus the radius of the circle: \[ \text{Length of the longest ray} = d + r \] Where \(r = \sqrt{145}\). Therefore: \[ \text{Length of the longest ray} = 12\sqrt{2} + \sqrt{145} \] ### Conclusion The length of the longest ray drawn from the point (4, 3) to the circle is: \[ 12\sqrt{2} + \sqrt{145} \]
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MCGROW HILL PUBLICATION-CIRCLES AND SYSTEMS OF CIRCLES -EXERCISE (LEVEL 1 ( SINGLE CORRECT ANSWER TYPE QUESTIONS ))
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  2. No portion of the circle x ^(2) + y^(2) - 16x + 18y + 1=0 lies in the

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  3. The geometrical mean between the smallest and greatest distance of the...

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  4. The length of the longest ray drawn from the point (4,3) to the circle...

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  5. If y pm a =0 is a pair of tangents to the circle x ^(2) + y ^(2) =a ^...

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  6. The circle x ^(2) + y ^(2) =9 is contained in the circle x ^(2) + y ^(...

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  7. The line (x-1) cos theta + (y-1) sin theta =1, for all values of theta...

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  8. Equation of the circle which cuts each of the circles x ^(2) + y ^(2) ...

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  9. The point at which the circle x ^(2) + y ^(2) + 2x + 6y + 4=0 and x ^(...

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  10. Find the equation of a circle which passes through the point (2,0) ...

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  11. If the limiting points of the system of circles x ^(2) + y ^(2) + 2gx+...

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  12. Find the length of the chord x^2+y^2-4y=0 along the line x+y=1. Also f...

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  13. Locus of the centre of the circle touching the line 3x + 4y + 1=0 and ...

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  14. Chord of the circle x ^(2) +y ^(2) = 81 bisected at the point (-2,3) m...

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  15. An equilateral triangle is inscribed in the circle x ^(2) + y ^(2) =1 ...

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  16. The centre and radius of a circle given by equation x =2 +3 cos theta,...

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  17. Consider two circes x ^(2) + y ^(2) =a ^(2) - lamda and x ^(2) + y ^(2...

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  18. Tangents drawn from the point P(1,8) to the circle x^(2) + y^(2) - 6x ...

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  19. The equation of a common tangent with negative slope to the circle x^2...

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