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If the circles x^2+y^2-16x-20y+164=r^2 a...

If the circles `x^2+y^2-16x-20y+164=r^2` and `(x-4)^2+(y-7)^2=36` intersect at two points then (a) `1ltrlt11` (b) `r=11` (c) `rgt11` (d) `0ltrlt1`

A

`r gt 11`

B

`0 lt r lt 1`

C

`r =11`

D

`1 lt r lt 11`

Text Solution

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The correct Answer is:
D
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