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If the straight line ax + by = 2 ; a, b!...

If the straight line `ax + by = 2 ; a, b!=0`, touches the circle `x^2 +y^2-2x = 3` and is normal to the circle `x^2 + y^2-4y = 6`, then the values of 'a' and 'b' are ?

A

`(-4)/(3)`

B

`(-5)/(3)`

C

`(-1)/(3)`

D

`(1)/(4)`

Text Solution

Verified by Experts

The correct Answer is:
C
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