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Let alpha, beta, gamma be the angles mad...

Let `alpha, beta, gamma` be the angles made by a line with the positive directions of the axes of reference in three dimensions. If `theta` is the acute angle given by
`costheta=(cos^(2)alpha+cos^(2)beta+cos^(2)gamma)/(sin^(2)alpha+sin^(2)beta+sin^(2)gamma)`, then `theta` equal.

A

`(pi)/(6)`

B

`(pi)/(3)`

C

`(pi)/(2)`

D

`(pi)/(4)`

Text Solution

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The correct Answer is:
To solve the problem, we need to find the value of the acute angle \( \theta \) given by the equation: \[ \cos \theta = \frac{\cos^2 \alpha + \cos^2 \beta + \cos^2 \gamma}{\sin^2 \alpha + \sin^2 \beta + \sin^2 \gamma} \] ### Step 1: Understand the Direction Cosines The angles \( \alpha, \beta, \gamma \) are the angles made by a line with the positive directions of the x, y, and z axes, respectively. The direction cosines are defined as: - \( \cos \alpha \) - \( \cos \beta \) - \( \cos \gamma \) ### Step 2: Use the Property of Direction Cosines We know that the sum of the squares of the direction cosines is equal to 1: \[ \cos^2 \alpha + \cos^2 \beta + \cos^2 \gamma = 1 \] ### Step 3: Express Sine in Terms of Cosine Using the identity \( \sin^2 \theta + \cos^2 \theta = 1 \), we can express the sine squares in terms of cosine squares: \[ \sin^2 \alpha = 1 - \cos^2 \alpha \] \[ \sin^2 \beta = 1 - \cos^2 \beta \] \[ \sin^2 \gamma = 1 - \cos^2 \gamma \] ### Step 4: Substitute into the Denominator Now substituting these into the denominator: \[ \sin^2 \alpha + \sin^2 \beta + \sin^2 \gamma = (1 - \cos^2 \alpha) + (1 - \cos^2 \beta) + (1 - \cos^2 \gamma) \] This simplifies to: \[ = 3 - (\cos^2 \alpha + \cos^2 \beta + \cos^2 \gamma) = 3 - 1 = 2 \] ### Step 5: Substitute Back into the Cosine Equation Now substituting back into the equation for \( \cos \theta \): \[ \cos \theta = \frac{\cos^2 \alpha + \cos^2 \beta + \cos^2 \gamma}{\sin^2 \alpha + \sin^2 \beta + \sin^2 \gamma} = \frac{1}{2} \] ### Step 6: Find the Angle \( \theta \) Now we need to find \( \theta \) such that: \[ \cos \theta = \frac{1}{2} \] The angle \( \theta \) that satisfies this equation in the range of acute angles is: \[ \theta = 60^\circ \text{ or } \theta = \frac{\pi}{3} \text{ radians} \] ### Final Answer Thus, the value of \( \theta \) is: \[ \theta = \frac{\pi}{3} \]
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