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The shortest distance between the skew l...

The shortest distance between the skew lines `bar(r) = bar(a_(1)) + lambda bar(b_(1)) "and" bar(r) = bar(a_(2)) + mu bar(b_(2))` is

A

`(|(a_(2)-a_(1)).b_(1)xxb_(2)|)/(|b_(1)xxb_(2)|)`

B

`(|(a_(1)-a_(1)).a_(2)xxb_(2)|)/(|b_(1)xxb_(2)|)`

C

`(|(a_(2)-b_(2)).a_(1)xxb_(1)|)/(|b_(1)xxb_(2)|)`

D

`(|(a_(1)-b_(2)).b_(1)xxa_(2)|)/(|b_(1)xxa_(2)|)`

Text Solution

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The correct Answer is:
A
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