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Sum of nitrogen atom in the monomers of ...

Sum of nitrogen atom in the monomers of nylon-6, and nylon-6,6 is x and sum of carbon atoms in them is 'y'. Then `(y)/(x)` is

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The correct Answer is:
6
Monomer of nylon-6 is caprolactum (one .N., sic .c.), Monomers of Nylon-6,6 are (i) HMDA (two .N. six .c.) (ii) Adipic acid (zero .N. six .c.) value of .x. is 3, value of .y. is 18, Then `(y)/(x) = (18)/(3) = 6`
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