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In a sample of a polymer, 100 molecules ...

In a sample of a polymer, 100 molecules have molecular mass `10^(3)` each and 200 molecules have molecular mass `10^(4)` each, the Number average molecular weight of polymer is `x xx 10^(3)` then 'x' is

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The correct Answer is:
7
`bar(M)_(n) = (sum NiMi)/(Sum Ni) = (100 xx 10^(3) + 200 xx 10^(4))/(100 + 200) = (10^(5) + 10^(5)(20))/(300) = (10^(5)(21))/(10^(2) xx 3) = (7 xx 10^(3)), x = 7`
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