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Osmotic pressure measurement of a polyme...

Osmotic pressure measurement of a polymer solution at `27^(@)C` gave a value for `(pi//c)_(0)` as `2.463 xx 10^(-4) "L atm " g^(-1)`. The `bar(M)_(n)` of the polymer `10^(x)`, x is

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The correct Answer is:
5
`bar(M)_(n)` of the polymer is `10^(5) , x = 5`
`(pi//c) = (RT)/(M_(n)) = 2.46 xx 10^(-4) = (0.082 xx 300)/(bar(M)_(n)), bar(M)_(n) = (0.082 xx 300)/(2.463 xx 10^(-4)) = 5 :. Bar(M)_(n) = 10^(5)`
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