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The rare law for a reaction between th s...

The rare law for a reaction between th substances A and B is given by Rate `=k[A]^(m)[B]^(n)` On doubling the concentration of A and halving the concentration of B, the ratio of the new rate to the earlier rate of the reaction will be as

A

`(m+n)`

B

`(n-m)`

C

`2^((m-n))`

D

`1/(2^((m+n)))`

Text Solution

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The correct Answer is:
C
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