Home
Class 12
CHEMISTRY
For N(2)O(5)("in CCl"(4))to2NO(2)+1/2O(2...

For `N_(2)O_(5)("in CCl"_(4))to2NO_(2)+1/2O_(2)`,
`K=6xx10^(-4)s^(-1)` at 350 K and `K=1.2xx10^(-3)s^(-1)` at 360 K. Then, when temperature is changed to 380 K, value of K `("in s"^(-1))`

A

`1.2xx10^(-3)`

B

`2.4xx10^(-3)`

C

`4.8xx10^(-4)` mole/lit/min

D

`4.8x10^(-3)`

Text Solution

Verified by Experts

The correct Answer is:
D
Promotional Banner

Topper's Solved these Questions

  • CHEMICAL KINETICS

    AAKASH SERIES|Exercise LEVEL-1 (EXERCISE -II ORDER, MOLECULARITY, HALF LIFE:)|34 Videos

  • CHEMICAL KINETICS

    AAKASH SERIES|Exercise LEVEL-II(LECTURE SHEET EXERCISE-I SINGLE & ONE OR MORE THAN ONE CORRECT ANSWER)|50 Videos

  • CHEMICAL KINETICS

    AAKASH SERIES|Exercise LEVEL-1 (EXERCISE -I MATCH THE FOLLOWING QUESTIONS:)|2 Videos

  • CHEMICAL KINETCS

    AAKASH SERIES|Exercise EXERCISE - 3.2|45 Videos

  • CHEMICAL THERMODYNAMICS

    AAKASH SERIES|Exercise Additional Practice Exercise|54 Videos

Similar Questions

Explore conceptually related problems

The rate equation for the decomposition of N_(2)O_(5) in "CC"l_(4) is rate =K[N_(2)O_(4)] where K=6.3x10^(-4)s^(-1) at 320 K. what would be the initial rate of decompositioni of N_(2)O_(5) in a 1.10 M solution of N_(2)O_(4) ?

The initial concentratin of N_(2)O_(5) in the following first order reaction N_(2)O_(5)(g) to 2NO_(2)(g)+(1)/(2O_(2))(g) was 1.24 xx10^(-2) mol L^(-1) at 318K. The concentration of N_(2)O_(5) after 60 minutes was 0.20xx10^(-2) mol L^(-1). Calculate the rate constant of the reaction at 138 K.

The initial concentration of N_(2)O_(5) in the first order reaction N_(2)O_(5)to2NO_(2)+1/2O_(2) was 1.24xx10^(-2) mole /lit at 318 k. The concentration of N_(2)O_(5) after 60 min is 0.20xx10^(-2) mole/lt. Calculate the rate constant of reaction at 318 K

At 1000 K, the equilibrium constant, K_(c) for the reaction 2NOCl(g) hArr 2NO(g) +Cl_(2)(g) is 4.0xx10^(-6) mol L^(-1) . The K_(p) (in bar) at the same temperature is (R=0.083" L bar K"^(-1) mol^(-4))

Let S(K) =1+3+5+….+(2K-1)=k^(2) +3 . Then which of the following is true?

K_(C) "for " H_(2) + 1//2 O_(2) rArr H_(2) O at 500 K is 2.4 xx 10^(47) . Now backward reaction is fovoured by

K_(C) "for " H_(2) + 1//2 O_(2) rArr H_(2) O at 500 K is 2.4 xx 10^(47) . Now backward reaction is fovoured by