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For the reaction 2N(2)O(5)to4NO(2)+O(2),...

For the reaction `2N_(2)O_(5)to4NO_(2)+O_(2)`, rate and rate constant are `1.02xx10^(-4)M"sec"^(-1)` and `3.4xx10^(-5)"sec"^(-1)` respectively then concentration of `N_(2)O_(5)` at that time will be (in moles /lit)

A

3

B

1.732

C

1

D

1.5

Text Solution

Verified by Experts

The correct Answer is:
A
`r=K.[N_(2)O_(5)]^(1),1.02xx10^(-4)=3.4xx10^(-5)xx[N_(2)O_(5)]^(1),[N_(2)O_(5)]^(-1)=(1.02xx10^(-4))/(3.4xx10^(-5))=(1.02xx10)/3.4=3`
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