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Thallium (I) is oxidized Ce(IV) as follo...

Thallium (I) is oxidized Ce(IV) as follows: `Tl^(+)+2Ce^(+4)toTl^(+3)+2Ce^(+3)`
Following are the elementary steps involved in the above reactionn
If rate `=k[Ce^(+4)][Mn^(+2)]` then catalyst intermediate and rate determining step are respectively

A

`Mn^(+2), Mn^(+3),1`

B

`Mn^(+2),Mn^(+3),2`

C

`Mn^(+2),Mn^(+4),1`

D

`TI^(+1),Mn^(+2),1`

Text Solution

Verified by Experts

The correct Answer is:
A, C
Constant`=Mn^(+2)`
Intermediate `=Mn^(+3),Mn^(+4),r=K[Ce^(+4)[Mn^(+2)]to` 1st step
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