Given that for a reaction of nth order the integrated rate equation is
`K=1/(t(n-1))[1/(C^(n-1))-1/(C_(0)^(n-1))]` where C and `C_(0)` are the concentration of reactant at time to initiallyh respectivley. The `t_(3//4)` and `t_(1//2)` are related as (`t_(3//4)` is time required to C to become C/4)

Options

A. `t_(3//4)=t_(1//2)[2^(n-1)+1]`
B. `t_(3//4)=t_(1//2)[2^(n-1)-1]`
C. `t_(3//4)=t_(1//2)[2^(n+1)+1]`
D. `t_(3//4)=t_(1//2)[2^(n+1)-1]`

Answer

A

Explanation

`(((t_(3))/4))/(((t_(1))/2))=[2^((n-1))+1]`