For the reaction:`[Cu(NH_(3))_(4)]^(2+)+H_(2)OhArr[Cu(NH_(3))_(3)H_(2)O]^(2+)+NH_(3)`
The net rate of reaction at any time is given by: rate `=2.0xx10^(-4)[[Cu(NH_(3))_(4)]^(2+)][H_(2)O]-3.0xx10^(5)[[Cu(NH_(3))_(3)H_(2)O]^(2+)][NH_(3)]`
The correct statement is (are)

Options

A. Rate constannt for forward reaction `=2xx10^(-4)`
B. Rate constant for backward reaction `=3xx10^(5)`
C. Equilibrium constant for the reaction `=6.6xx10^(-10)`
D. At equilibrium, net rate =0

Answer

A, B, C, D

Explanation

`K_(f)=2xx10^(-4),K_(b)=3xx10^(5),`
`K_(c)=(K_(f))/(K_(b))=(2xx10^(-4))/(3xx10^(-5))=0.666xx10^(-9)=6.66xx10^(-10)`